If a=√(7+4√3), what will be the value of a+1/a?
If roots of equation (a^2+b^2)x^2-2b(a+c)x+b^2+c^2=0 are equal then a, b, c are in
A) AP
B) GP
C) HP
D) cannot be determined
Solve the inequality
3x^2-7x-6<0
3x2 – 7x – 6 < 0.
3x2 – 9x - 2x – 6 < 0.
3x ( 3x -2) -2( x-3) < 0.
( 3x – 2) ( x-3) <0
2/3 3
___+ve____|_____-ve _____|____+ve___
2/3 < x < 3
(7/2+a)²+(7/2+a+x)²=7²-----(1)
(7/2+a-x)²+a²=(7/2)²-----(2)
Find values of a and x ?
22nd: 3s+5t=750. First solution will be, s=0, t=150. Now, value of t will go down by 3 (which is coefficent of s) for every next solution. Next solution is s=5, t=147, then next will be, s=10, y=144 and so on. Value of t will vary from 150 to 0, with common difference of 3. Hence number of solutions will be {(150-0)/3} +1=51.
If you want to find out natural solutions, then 51-2=49. We subtract 2 because of (0,150), and (250,0).
1. How many integral pairs (x, y), where 0< x, y < 1000, satisfy 141x + 517y = 4158?
A. 0
B. 1
C. 2
D. More than 2
The HCF of 141 and 517 is 47. But 47 does not completely divide 4158. Therefore, there are no integral solutions of the equation. Hence, option A.
These questions are very difficult.
Great thread , it covers the important equations and question. i also got answer of my question in this post.
Thank You