1/4 of (Area of the square ABCD - area of the smaller circle ) = 1/4 of (100 - 39.2) = 15.2 %
Hello sir , please solve question 6 and 7 -
Alternate approach:
In a regular hexagon with side a, the smaller diagonal is √3a and other one is 2a
Now in this question length AC is a smaller diagonal where a=1
Therefore AC= √3
and area of sq.= √3*√3=3cm sq
Q. 7.
Out of the six surfaces 4 are rectangular
13 x 20 + 13 x 20 + 20 x 20 + 10 x 20 + 2 x ( area of trapezium )
520 + 600 + 360 = 1480 square units .
Area = height*(perimeter of base trapezium) + 2*area of base which is trapezium)
Sir, why isn't the answer 10925? I got 10900 and 1/4th of the tile with side 1 would cost Rs 25
Hexagon ABCDEF is inscribed in a circle. The sides AB, CD and EF are each x units in length whereas the sides BC, DE and FA are y units in length. Then the radius of the circle is ?
In the rectangle ABCD, the perpendicular bisector of AC divides the longer side AB in a ratio 2:1. Then the angle between AC and BD is .