A shopkeeper buys an article at ` 12000 and spends 10% of cost price as a transport. He marked price 20% above the price at which he buy and sells at mark marked price, find his profit percent.

**Amal purchases some pens at ₹ 8 each. To sell these, he hires an employee at a fixed wage. He sells 100 of these pens at ₹ 12 each. If the remaining pens are sold at ₹ 11 each, then he makes a net profit of ₹ 300, while he makes a net loss of ₹ 300 if the remaining pens are sold at ₹ 9 each. The wage of the employee, in INR, is**

**Answer :-**

Let’s consider the total number of pens to be

(100 +x)

Let's consider the fixed-wage of the labour to be ‘w’

case (i): the net profit is 300

CP = 8(100 +x) + w

SP = 12 x 100 + 11 x = 1200 + 11x

Profit = SP - CP

300 = 1200 + 11x - 8(100 +x) - w

w - 3x = 100 → eq(1)

Case (ii): the net loss is 300

CP = 8(100 +x) + w

SP = 12 x 100 + 9 x = 1200 + 9x

Loss = CP - SP

300 = 8(100 +x) + w - 1200 - 9x

w - x = 700 → eq(2)

By solving equation (1) & (2) we get w = 1000.

Therefore, the wage of the employee is 1000.

Alternate solution:

We can also do this with a little intuition. The Rs 2 decrease per pen results in 300 loss from the case of 300 profit.

The net value of 600 resulted by selling the remaining pens at Rs 2 lesser.

If the number of remaining pens is x, then 2x = 600

So, x = 300.

Total pens = 100 + 300 = 400.

We can get the wage of an employee(w) by considering profit/loss

Profit = 300

100(12) + 300(11) - 400(8) -w = 300

w = 1000

If we rolled a dice 3 times. In how many ways we can get a sum of 8?

(6,1,1) = 3 ways

(5,2,1) = 6 ways

(4,2,2) = 3 ways

(4,3,1) = 6 ways

(3,3,2) = 3 ways

The total no. of ways = 21 ways

In how many ways we can pick 4 numbers from first 20 natural numbers such that there is at least a gap of one number between any two picked numbers?

ANSWER 2

Numbers before we pick first number = A

Numbers between first and second number = B

Numbers between second and third number = C

Numbers after we pick fourth number = D

ATQ,

A+B+C+D=16 [A≥0, B≥1, C≥1, D≥0]

A+B+C+D=14 [A≥0, B≥0, C≥0, D≥0]

NO OF WAYS= 14C2 = 91 WAYS

If cost price of 36 apples is equal to selling price of 30 apples and discount on 14 apples is equal to profit on 8 apples. Find the profit % and discount%.

If the selling prices of two articles is same and first article is sold at 20% profit and second article is sold at 20% loss. Find the overall profit or loss percent?

Q1. A person spent Rs 50000 to purchase a desktop computer and a laptop computer. He sold the desktop at 20% profit and the laptop at 10% loss. If overall he made a 2% profit then the purchase price, in rupees, of the desktop is?

Sir,

D = Price of Desktop and L = Price of Laptop

0.2 D – 0.1 L = 2 % of 50000

0.2 D – 0.1 L = 1000

2D – L = 10000

D + L = 50000

Solving D = 20000

Q1. On selling a pen at 5% loss and a book at 15% gain, Karim gains Rs. 7. If he sells the pen at 5% gain and the book at 10% gain, he gains Rs. 13. What is the cost price of the book in Rupees?

A-80

B-85

C-100

D-95

Selling price = 1.2 x 12000 = 14400

Cost price = 1.1 x 12000 = 13200

Profit = 14400 - 13200 =1200

Profit % = (1200/13200) x 100 =300/33 =100/11 = 9 1/11 %

Answer is b

A dishonest dealer claims to sell a product at its cost price . He uses a counterfeit weight which is 20% less than the real weight . Further he added 20% impurities to the product . Find the net profit percentage of the dealer !

Hello Tarishi ,

Assume 100g costs 100 and adds 20% impurity

100g will become 120g

now instead of using 100 gm weigh he is using 80 gm weight

so 100g weight using counterfeit weight becomes (120/ 80 ) x 100 = 150 .

Hence profit percentage => 50%

Dev bought 100 kg rice for RS 1100 and sold it at a loss of as much money as he received for 20kg of rice. At what price did he sell the rice?

Hello Richa

We know ,

Selling Price = Cost Price - Loss

Hence , SP of 100 kg = CP of 100 kg - SP of 20 kg

SP of 120 kg = CP of 100 kg

SP : CP = 10 : 12

Hence SP of 100 kg rice = 10 x 1100/12

or Rs 55/6 per kg

let diameter of can be 10 and h be 1

earlier

v= 10*10*1= 100kg

now,

v=9*9*1 =81 kg

now let 1 kg = 1 rs.

earlier we were selling 100kg for 100rs

now we will sell 81 kg for 100 rs

means c.p =81

s.p =100

profit % =(19/81)*100 =23.47 (aprox)

earlier we were having zero profit now 23.47 so change =23.47

The previous profit percentage is not known, so we cannot calculate the increase in profit percentage.

Hence , Option D

A dishonest shopkeeper cheats at the time of purchasing by 20% and at the time of selling by 35% using wrong weights and sells at the cost price.find his profit %

Make a cheating of 20% while buying item means while buying he brought item worth Rs 120 in Rs. 100

Now at the time of selling he cheats 35% . So he sells item worth Rs 120 in price of 120 x (100/65) =Rs 184.6

hence profit percentage becomes : 84.6% .

One year payment to a servant is rs. 200 and one shirt. The servant leaves after 9 months and recieves Rs. 120 and a shirt. find the price of the shirt.

a. 80

b. 100

c. 120

d. Can't be determined

Let the price of the shirt be x .

Total yearly income = 200 + x.

Monthly = (200 + x)/12

9 months income = [(200 + x)/12] × 9

Now ,

120 + x = [(200 + x)/12] × 9

x = 120 .

Alternate Approach :

Loss of ₹80 in 3 months so in 12 months => ₹320

Contract is 200 + shirt.

So Shirt = 320 - 200 = ₹120

Deb ought 100kg of rice for Rs. 1100 and sold it at a loss of as much money as he received for 20kg of rice. At what price did he sell the rice?

a. 10.20

b. 10

c. 9.16

d. 9

Same question has been posted earlier... Got the solution...thanks!