20/02/2018 5:47 pm
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Ratio - proportion, Time and work
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A bag contains 50 p, 25 P and 10 p coins in the ratio 3: 5: 7, amounting to Rs 345. Find the number of coins of each type.
(a.) 300, 200,600
(b.) 300,500,700
(c.) 200,600,180
(d.) 600,200,700
(e.) None of these
37 questions & discussions are there under this sub-topic
0
22/02/2018 2:19 pm
Let number of coins of 50P, 25P, and 10 p are respectively 3c, 5c and 7c.
3c x 50 + 5c x 25 + 7c x 10 =34500
150c + 125c +70c = 34500
345c= 34500
c = 100
Number of coins = 300, 500, 700
0
31/03/2018 2:56 pm
Two number P and Q are such that sum of 60% of P and 30% of Q is equal to the 50% of sum of P and Q. Find the ratio of Q : P.
(a.) 1 : 2
(b.) 2 :1
(c.) 3 : 2
(d.) 2 : 3
(e.) 2 : 5
0
31/03/2018 2:56 pm
Hi Tin,
Please find the answer
60% of P + 30% of Q =50%(P+Q)
6P+3Q=5P+5Q
P=2Q
P:Q=2:1
0
13/06/2018 1:40 pm
Consider n a 2 digit number such that the ratio of the number to the sum of its digit is maximum. How many such numbers exist?
TG Team 13/06/2018 5:15 pm
Let the two digit number be N = 10X+Y ,
(10X + Y)/(X+Y) should be maximum ,
i.e [9X + (X + Y)]/(X+Y) should be maximum
i.e. 9X/(X+Y) should be maximum
For the expression to be maximum y must be 0. And X can take any values from 1 to 9.
Hence , 9 two digit numbers.
10,20,30,..... and 90.
0
14/07/2018 8:43 pm
Sheetal has only three types of earrings- Gold, Diamond and Silver. All her earrings except X are Diamond, all except Y are Gold and all except Z are Silver. If the ratio of X:Y:Z = 25:12:17, then what is the ratio of the number of Gold earrings to the number of Silver earrings?
TG Team 15/07/2018 12:20 pm
Hello Samyak!
X = Gold + Silver = 25x
Y = Silver + Diamond = 12x
Z = Diamond + Gold = 17x
( X + Y + Z ) = 2 ( Diamond + Gold + Silver ) = 54x
Diamond + Gold + Silver = 27x
Gold = 27x - Y = 15x
Silver = 27x - Z = 10x
Gold : Silver = 15x : 10x = 3 : 2 .
0
18/07/2018 1:01 am
Three brothers A, B and C, work together in a company and their total monthly salary is Rs. 25000 per month. They spend 75%, 80%, and 90% of their income respectively. And their saving are in the ratio of 25:18:6.
find individual salary of all three?
ABHISHEK LEELA PANDEY 19/07/2018 1:20 pm
This question is an excellent application of ratios. We can solve it by assuming the salaries of the three brothers to be a, b and c.
Savings:
A= 0.25 a
B= 0.2 b
C= 0.1 c
According to the question
0.25 a = 25 k
0.2 b = 18 k
0.1 c = 6 k
which transforms to
a = 100 k
b = 90 k
c = 60 k
As we know,
a + b + c = 250 k
or
25000 = 250 k
or
k = 100
Individual Salaries
A = 100 k = INR 10000
B = 90 k = INR 9000
C = 60 k = INR 6000
0
21/07/2018 7:43 pm
Sir please tell me the solution of this problem.
ABHISHEK LEELA PANDEY 22/07/2018 12:48 pm
Hello Samyak !
Let the number of balls with :
Abhinav = 5a
Bipin : 12b
Chetan = 13c
The sum of the number of balls should be equal to 60 , as no ball is remaining in the boxes .
5a + 12b + 13c = 60
the only solutions satisfying the above equation are ( 7, 1 , 1 ) and ( 2 , 2, 2 )
a < 7 because 5a is less than or equal to 30.
Hence the answer is 10 , 24 and 26 . 🙂
0
15/08/2018 4:10 am
In two alloys, respective ratios of copper and zinc are 4 : 1 and 1 : 3. Ten kg of the 1st alloy, 16 kg of the 2nd alloy and some quantity of pure copper are melted together. In the resultant alloy the ratio of copper to zinc is 3 : 2. Find the weight (in kg) of the new alloy.
How to handle such problems?
TG Team 15/08/2018 12:03 pm
Calculate the quantity of zinc in mixture of both the alloys -
10 × 1/5 + 16 × 3/4 = 14
This 14kg of zinc is 2/5 of the new alloy, hence total weight of alloy is 14× 5/2
=35kg
0
17/09/2018 4:21 pm
Sir , kindly share the solution to this problem-
At the NSB demonstration , supporters of Ms. P outnumbered the police by 9:1. The police arrested 135 NSB supporters averaging 5 for every 3 policemen. How many supporters of NSB were there in the demonstration?
TG Team 17/09/2018 7:27 pm
Number of police involved : (135/5 ) x 3 = 81
Ratio of police involved : supporters of Ms. P = 1 : 9
Hence => 81 x 9 = 729.
0
24/09/2018 3:49 pm
TG Team 24/09/2018 5:16 pm
Let the number of apples be A and number of Mangoes be B
Now CP of each apple => x , SP of each apple => 2x .
CP of Each mango => 2x , SP of each mango => 6x
Profit = Total SP - Total CP = (2Ax + 6Bx) - ( Ax + 2Bx) =150% of ( Ax + 2Bx)
Ax + 4Bx = 3/2 ( Ax + 2Bx )
Ax = 2Bx
A : B = 1 : 2
0
01/10/2018 12:58 pm
Sahil employ 200 men to build a building. They finish 5/6of work in 10 weeks. Because of some natural calamity not only does the work remain suspended for 4 weeks but also half of work already done is washed away. After the calamity , when work is resumed, only 140 men turn up. The total time in which contractor is able to complete the work assuming that there are no further disruptions in the schdule is
a 25 weeks
b 26weeks
c 24weeks
d 20 weeks
aniket prajapati 01/10/2018 11:24 pm
apply (men*days)/work
after calamity half of the work done is destroyed which is 5/12 and now remaining work to be done=1-5/12=7/12
(200*10)/(5/6)=140*weeks/(7/12)
weeks =10
so total time taken=10+4+10 =24 weeks
0
01/10/2018 1:01 pm
concentrations of three types of milks X,Y and Z are 10%, 20%and 30% respectively. They are mixed in ratio 2:3:P resulting in a 23% concentration solution. Find P
TG Team 01/10/2018 6:43 pm
Take 200ml of first solution , 300 ml of 2nd solution and 100p ml of third solution :
Now , solve the following equation
20 + 60 + 30p = (23/100) ( 200 + 300 + 100p)
80 + 30p = 23 ( 5 + p)
p = 7
aniket prajapati 01/10/2018 11:31 pm
Alternate approach
you can solve by average
(10*2 + 20*3 +30*p)/(2+3+p) =23
80 +30p=115+23p
7p=35
p=5
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