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@raman1729
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Topics: 24 / Replies: 431
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6 years ago
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RE: Ratio and Proportion

S – Kn2 at n = 4 , S – K42 = 120 … (1) at n = 6 , S – K62 = 60 … (2) From (1) and (2) S = 168 and K = 3. So 168 - 3n2 Should be greater than 0. 168 -...

6 years ago
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RE: Divisibility and Remainders

1 x 2 x 3 x 4 x 5x ...... x 13 i.e 13! is a multiple of 16 . Hence 13! raised to any power would be a multiple of 16. Therefore the remainder will be...

6 years ago
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RE: Time and Work

Let the time in which tank will be filled is x minutes So, x/60 + ( x -10)/30 + ( x-20)/20 = 1 on solving x = 70/3 i.e 23 minutes 20 seconds Hence ,...

6 years ago
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RE: Miscellaneous

1. _ _ _ _ 0 _ _ _ _ : for first four digits there are 9C4 ways , for last four digits there are 5C4 ways. => 9C4 x 5C4 = 630 numbers _ _ _ _ 1 _ _...

6 years ago
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6 years ago
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RE: Divisibility and Remainders

N = DQ + 52=> 5N = D (5Q) + 52 x 5 5N = 5DQ + 260 Also 5N = Dx + 4 So , D divides (260 - 4) i.e 256 hence , All factors of 256 > 52 . [ 256 , 1...

6 years ago
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RE: Divisibility and Remainders

(Any odd number )^ (4k ) ends with 1 or 5 *( odd multiples of 5 )^(Any natural number ) ends with 5. (Any even number )^4k ends with 6 or 0 *(Even m...

6 years ago
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RE: Divisibility and Remainders

25 pages consist of 25 odd numbers and 25 even numbers So there sum should always be odd Hence 1900 an even sum is never possible.

6 years ago
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RE: Divisibility and Remainders

Since digits of 10digits number n sum to 45 , n should be divisible by 9n should be divisible by 99999 10 digits number will be of typen = 100000x + y...

6 years ago
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RE: Divisibility and Remainders

77777...... 1001 times Any digit repeated 6 times is always divisible by 1001 so 77777.... Written 996 times is a multiple of 1001 Hence , 7...

6 years ago
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RE: HCF and LCM

B is multiplied by 25, LCM (A,B) remains unchanged so A has 5^3 in its prime factorization . When A is multiplied by 8 ,LCM (A,B) remains unchanged so...

6 years ago
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RE: Miscellaneous

Total number of flowers : T (Tn/100) + 20 = (T + 20)( n + 10)/100 Tn + 2000 = Tn + 10T + 20n + 200 1oT + 20n = 1800 10T = 1800 - 20n T = 180 - 2n n c...

6 years ago
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RE: Miscellaneous

The quicker way to calculate last three digits of a number is to calculate the remainder by 1000. 1000 = 125 x 8 79999/8 = (-1)9999 = -1 or 7. 79999/1...

6 years ago
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