Hello sir,

Please help me with the approach.

Q1. In a circle of radius 11 cm, CD is a diameter and AB is a chord of length 20.5 cm. If AB and CD intersect at a point E inside the circle and CE has length 7 cm, then the difference of the lengths of BE and AE, in cm, is?

Ans – 0.5

The idea that we use here is remarkably simple.

We know, the product of rectangles formed by two intersecting chords are always equal

So, AE x EB = CE x ED

AE x EB = 7 x 15

Also, we know that AB = 20.5 cms = AE + EB

So, the Sum of AE and EB must be 20.5 and their product must be equal to 7 x 15

7 x 15 = 105

The numbers must be close to each other, for their sum to be 20.5

From trial and error, we find their values to be 10 and 10.5 cms respectively

So, AE x EB = 7 x 15

10 x 10.5 = 7 x 15

Difference = 10.5 - 10 cms = 0.5 cms

Q1. AB is a diameter of a circle of radius 5 cm. Let P and Q be two points on the circle so that the length of PB is 6 cm, and the length of AP is twice that of AQ. Then the length, in cm, of QB is nearest to ?

Hello Abhi !

Alternate Approach :

please share the solution to this problem

Ohh thank you. The question says to find the length of tangent from the center of one circle to the other, I thought it meant from one center to the other center. The question wasn't clear to me.

Hello Sir, please help me with the below 2 questions:

Q1) Two circles of radii 14 and 22 units are 45 units apart at the centers. What is the length of their common internal tangent?

Q2) A square whose area is 64 is partitioned into four congruent smaller squares. Find the circumference of the circle that passes through the centers of the four subsquares.

Hey sir, please help me with the below question.

Sir, how do we know that angle CAB is 60°?

Or if I put it in different term- how do we know that triangle ABC is an equilateral triangle?

Please help.

AC and AB are circular arcs so

AC = AB = BC = r ( Radii )

Hence , ABC is an equilateral triangle .

o is the centre of the circle please provide the solution

In the rectangle ABCD , the perpendicular bisector of AC divides the longer side AB in a ratio 2:1 . Then the angle between AC and BD is?

Sir the figure is troubling me

Hi sir, please share the solution

Hello Richa ,

All the options seem wrong the correct answer is 10 - 2sqrt{15}

Hi sir, please help with this problem

Join E - A and D - A

the angle formed ( EAD ) will be 30º

So the angle formed by the side of the square at center = 60º

Hence, Equilateral triangle

Radius = Side of the square = 2

Sir, can you help me with the diagram of this question? I'm not able to visualize or draw the diagram.

AB and CD are perpendicular to a diameters of Circle O. Let CM be a chord that intersect AB at E, so that CE=6 and EM =5. Find the circumference of the circle.