Hello sir, Please help me with the approach.[attach]19[/attach]

Q1. In a circle of radius 11 cm, CD is a diameter and AB is a chord of length 20.5 cm. If AB and CD intersect at a point E inside the circle and CE has length 7 cm, then the difference of the lengths of BE and AE, in cm, is?

Q1. AB is a diameter of a circle of radius 5 cm. Let P and Q be two points on the circle so that the length of PB is 6 cm, and the length of AP is twice that of AQ. Then the length, in cm, of QB is nearest to ?

Hello Abhi ! [attach]21[/attach]

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20/11/2018 10:42 pm

Richa

(@richa)

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Hi Sir, please help.

aniket prajapati 21/11/2018 11:22 am

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22/11/2018 5:16 pm

Ridhima Mehta

(@ridhima-mehta)

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solution please

TG Team 23/11/2018 1:58 pm

46750639 1913551725429116 6906761085068509184 o

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21/11/2019 6:37 pm

tanvi

(@tanvi)

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In a circle chords ab and cd intersect perpendicularly at p. If ap= 20, pb= 36, and cp= 24, then the perimeter of the circle is.

This post was modified 5 years ago by tanvi

Aditya Dang 21/06/2021 3:11 pm

Perimeter of circle is 2pi(793)^1/2.

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20/11/2020 9:34 pm

Amrita Mirchandani

(@amritamirchandani)

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a)96 b) 75 c)80 d)88

TG Team 20/11/2020 10:13 pm

@amritamirchandani
Hi Amrita,
Let the radius of the larger circle R. So
AB × BC = FB² ( Chord Intersection Theorem)
R (R-42) = (R -24)²
R = 96
Now AC = AD - CD = 2 × 96 -28 = 150
Radius of the smaller circle => AC/2 = 75

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