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If three sides of a rectangular park have a total length of 400 ft, then area of park is maximum when length(in ft) of its longer side is ?

 

Anonymous 05/03/2018 11:41 am

Let the length and breadth of the park be l and b, l > b
Case 1: 2l + b = 400
Area = lb. Area is maximum when 2l * b is maximum, which is maximum when 2l = b

=> l = 100, b = 200. Which can't happen since l > b

Case 2: l + 2b = 400
Area = lb. Area is maximum when l *2 b is
maximum, which is maximum when l = 2b

=> l = 200, b = 100.

Hence the length of the longer side is 200 ft

21 questions & discussions are there under this sub-topic
2

What is the diameter of largest hemisphere that can be inscribed in a cube of edge length 1?

√3(√3 - 1)

0.4√6(√6 - 1)

√3

1

aniket prajapati 13/10/2018 3:11 pm
This post was modified 6 years ago by aniket prajapati

Place a hemishphere such that ends of it's diameter coincide with opposite vertices of any face of cube

Diameter = diagonal of cube =a√3 

Here a=1 

So diameter of hemishphere =√3

You can check that other values are less than √3 hence option (c)

Utkarsh Garg 13/10/2018 3:16 pm

But the correct ans is option (b)

Utkarsh Garg 13/10/2018 3:18 pm
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Utkarsh Garg 15/10/2018 10:20 am

solution please..

aniket prajapati 16/10/2018 11:30 pm

diameter will be greater than 1 and less than √2 hence only 2 option satisfies 

Utkarsh Garg 16/10/2018 11:49 pm

why less than √2 ?

aniket prajapati 16/10/2018 11:56 pm
This post was modified 6 years ago by aniket prajapati
mens

place a bowl in a box you will notice that the bowl is tangent to 2 adjacent faces and those two points will be on the square as shown in the figure so we can conclude that it will be less than diagonal of the square which √2 

this is my theory I may be wrong I tried it today and got this way I tried to make this figure 

if you come up with a better solution or any strong point against it please do share in future

try it practically

traciblack 26/12/2022 10:13 am
0

A sphere is inscribed in a cone whose radius and height are 12 and 16 units, respectively. Then, the volume of the sphere is

Choose one answer.
  a. 256pi
  b. 288pi
  c. 216pi
  d. 312pi
TG Team 03/07/2018 6:00 pm

Hello Kinshuk ! PFA the solution : 

IMG 20180703 175750
0
1527924332689625867304
TG Team 03/07/2018 5:54 pm

The solution of Question  Number 27. 

IMG 20180701 135557
TG Team 03/07/2018 5:54 pm

Alternate Approach : 

104 IMG20180701135605
0
20180821 212940
aniket prajapati 23/08/2018 10:39 pm
This post was modified 6 years ago by aniket prajapati
anik

 

PFA ,

bigger cube will be converted into cube of dimension (6*6*6)

u can see one face of cube in figure those which are coloured will only be painted on one side and the cubes in edges will be coloured in more than 1 side

hence for 1 face =4*4=16

for six face =16*6=96

0

A regular tetrahedron of length 12 cm is accommodated in a sphere such that all its vertices touch the sphere. Find the radius of the sphere.                  Options : 1)7.2 cm  2)7 cm  3)7.5 cm  4)6.5 cm

aniket prajapati 25/09/2018 11:43 pm

in tetrahedron height h = (√6/3)a where a = length of an edge

so, in this case, h=(√6/3)*12 which is (√6)*4

we know the height of tetrahedron is divided in the ratio of 2:1 from the centre of the sphere or   centroid of the tetrahedron 

so radius of sphere =(2/3)*(√6)*4=8*2.44/3

                                  =19.52/3=6.5 

hence option (4) is correct 

aniket prajapati 26/09/2018 12:21 pm

Sorry for the wrong solution here is the right one 

IMG 20180926 121951
aniket prajapati 26/09/2018 12:25 pm

U can also learn directly 

Radius of sphere inside tetrahedron= h/4

And radius of sphere circumscribing tetrahedron =3h/4

0
43027524 2217096361909096 250601897088516096 n
0

How many of the following rectangle cannot be divided in two equal parts which can be rearranged to form a square?

16×9

18×8

24×6

36×4

aniket prajapati 18/10/2018 12:01 am

all of these?

 

Utkarsh Garg 18/10/2018 12:05 am

The given ans is 36x4.

0

Find the number of different shortest paths from point A to point B in a city with perfectly horizontal streets and vertical avenues as shown in figure. No path can cross the fenced off area shown in grey in the figure. 

 

16

17

19

aniket prajapati 17/10/2018 11:51 pm

17 is answer?

 

Utkarsh Garg 17/10/2018 11:55 pm

yes.

aniket prajapati 17/10/2018 11:58 pm
prob
0

The height of a trapezoid whose diagonals are mutually perpendicular is equal to 4. Find the area of the trapezoid if it is known that the length of one of its diagonal is equal to 5. 

ans: 50/3

0

The parallel sides of a trapezium are of 6 units and 8 units respectively. Find the length of the line segment parallel to these sides and which divides the area of the trapezium in equal halves.

 

 

4√3      

5√2  

TG Team 12/11/2018 10:07 am

8² - x² = x² - 6² 

 

2x² = 8² + 6²

 

x = 5√2 

0

ABCD is a square. P and Q are points on the sides, as shown, such that BP: PC = 3: 1 and BQ: AQ =    2: 1. Find the ratio of the area of the shaded region to the area of the square ABCD.

 

5/12                       

7/24

TG Team 13/11/2018 1:38 pm
46047385 1900656313385324 8812003797275508736 o
0

Sir , kindly share the solution to this problem -

IMG 20181113 164426 EDIT 1 EDIT 1 (1)
aniket prajapati 13/11/2018 9:45 pm
WhatsApp Image 2018 11 13 at 9.43.36 PM
0

A cube is divided into two parts by a plane passing through three non-adjacent vertices. Find the ratio of volume of the smaller part to that of larger one.

Ans: 1:5

aniket prajapati 15/11/2018 12:14 pm
15422641959682089966141
0

Sir , please share the solutions of questions 25 and 26 -

IMG 20181115 225009
TG.Raman 15/11/2018 11:31 pm
26
TG.Raman 15/11/2018 11:32 pm

26. 

Let the larger radius be x. By the power of a point theorem,
AB BC = FB2
x(x-42) = (x-24)2
6x = 242,
x = 96.
Now the smaller radius is AC/2 = (AB+BC)/2 = (2x -42)/2 = x-21 = 75. Hence the radius of the smaller circle = 75.

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