Three Cases (1) none of them 0 . x + y + z = 10 => `14C2 14C2 x 8 = 728 cases (2) One of them 0. 3C2 x 14 = 42 42 x 4 = 168 cases (3) Two 0. ...
For last three digits in binary divide the number by 2^3 i.e 8 . So 43211724 = 724 mod 8 4 mod 8 . 4 in base 2 => 100.
Alternate Approach : Total : 9C4 = 126 remove cases when there is no girl and 1 girl. So , 126 - 4C4 - 5c1 x 4C3 = 126 - 1 - 20 = 105
Solution to the question 36 . Let box 1 contains black, others white. Similarly box 2 black, others white..so on. Therefore, case of one box contai...
Decimal representation of 1116 = 62 x 1 + 6 x 1 + 1 = 43 Decimal representation of 11116 = 63x1 + 62x 1 + 6 x 1+ 1= 259 . Now , count multiples of 9 b...
5th ABCD B > C > D. A can take 9 values . ( 1, 2, 3, 4,...., 9) For D = 1 , select B and C from ( 2 , 3, 4, ... 9) in 8C2 ways . For D = 3 , sel...
6th . other than these 3, there are 5 persons. between these persons there are 6 gaps. the chosen 3 can be anywhere in these 6 gaps , So 6C3 = 20 ways...
(x + y ) x = 2418 = x² + xy ... ( 1) ( x + y)y = 3666= y² + xy ... (2) on adding (1) and (2) x² + 2xy + y² = 6084 ( x + y)² = 78² x + y = 78 x = ...
TTT | AAAHG_ A _ A _ A _ H _ G_: Arrange these letters in 5!/3! i.e 20 ways space among these letters : 6 . Select any three spaces in 6c3 ways Hence...
Solution to the 27th Question : let 100 items cost 100Rajesh will take away 110 items Hence , CP of Rakesh => 110 Marked price for Rajesh : 100 x 1...
Yes! But, it is an approximate value and its accuracy reduces as the interest rate becomes high.
First, this question is more in line with the CR questions you are likely to get on the GMAT. However, the process of reasoning involved is what you m...
The digital sum of a number N is same as the remainder obtained by dividing the number N by 9. Digital sum of the product 2 x 7 x 181 x 241 x 607 is ...